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AnswerCategory: ChemistryWhat is the mass of each product
admin Staff asked 2 months ago

What is the mass of each product 

If there is 30.0 grams of ammonium nitrate and 50.0 grams of sodium phosphate, what is the mass of each product that can be formed, and the mass of the excess left over?

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1 Answers
admin Staff answered 2 months ago

Balancing the equation we get,
3 NH4NO3 + Na3PO4 = (NH4)3PO4 + 3 NaNO3
Molecular weight of NH4NO3 is 80.043 g/mol
So, converting it to moles we get,
(30.0 g NH4NO3) / (80.043 NH4NO3 g/mol)
= 0.37480 mol NH4NO3
Molecular weight of Na3PO4 is 163.941 g/mol
So, converting it to moles we get,
(50.0 g Na3PO4) / (163.941 Na3PO4 g/mol)
= 0.30499 mol Na3PO4
0.37480 mol of NH4NO3 would react completely with 0.37480 * (1/3) mol of Na3PO4
= 0.12493 mol of Na3PO4
But the amount of Na3PO4 is more than that of NH4NO3. So, Na3PO4 is in excess.
Mass of products: (NH4)3PO4 and NaNO3:
(0.37480 mol of NH4NO3) * 1 mol (NH4)3PO4 / 3 mol NH4NO3) * (149.086 (NH4)3PO4 g/mol) = 18.6 g (NH4)3PO4
(0.37480 mole of NH4NO3) * (3 mol NaNO3 / 3 mol NH4NO3) * (84.9947 NaNO3 g/mol) = 31.9 g NaNO3
Mass of excess left over:
{(0.30499 mol Na3PO4 initially) – (0.12493 mol Na3PO4)} * (163.9407 Na3PO4 g/mol) = 29.5 g Na3PO4 will be left over.