Are there any metallic compounds that do not react with acid or base?

What is the history of mercury drug?

After reaching saturation, if the temperature of the room continues to decrease for one more hour, h…

How can the mass of mixture of solids (initial), mass (g), and percentage of total mixture (%) be ca…

What is the number of moles and the mass of Barium peroxide (BaO2) needed to produce 2.500 kg of Bar…

This is when the hydrogen atom’s electron in the n = 4 quantum level of a Bohr atom drops to the ground state (i.e. n = 1).

It will be helpful if I can get a diagram to illustrate each of the possible transitions responsible for the spectral lines.

1 Answers

According to Bohr’s equation, the energy change of an electron while returning to a lower energy state from its excited state is given by the formula, Energy difference (E) = Ef – Ei where Ef or Ei = -2.18 * 10^-18 J (1/n^2). Here n is the number of orbit. nf means the higher energy state and ni means the lower energy state. Similarly Ef means energy in the higher energy state and Ei means energy in the lower energy state. So in this case, if we put Ef = 4 and Ei = 1 in the above mentioned formula, then,

Ef = -2.18 * 10^-18 (1/4^2)

= -1.36 * 10^-19

Ei = -2.18 * 10^-18 (1/1^2)

= -2.18 * 10^-18

Energy difference = Ef – Ei

= -1.36 * 10^-19 – (-2.18 * 10^-18) J

= -2.04 *10^-18 J