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Use 1.007825 amu as the mass of 1/1H (mass of a proton and an electron). The answer has to be expressed in atomic mass units to 6 significant figures.
Use 1.008665 amu as the mass of 1/0N (mass of a neutron). The answer has to be expressed in atomic mass units to 7 significant figures.
Use 18.9984 amu as the actual mass of 19/9F. The answer has to be expressed in atomic mass units to the fourth decimal place
There are 9 electrons, 9 protons and 10 neutrons in 19/9F.
As the mass of a proton and an electron is 1.007825 amu,
so, total mass for electrons and protons:
9 * 1.007825 amu = 9.07042 amu
As the mass of a neutron is 1.008665 amu,
so, total mass for neutrons,
10 * 1.008665 amu = 10.08665 amu
Thus, calculated total mass = 9.07042 amu + 10.008665 amu = 19.15708 amu
The actual mass of 19/9F is 18.9984 amu
Thus, mass defect = mass of product – mass of reactants
= 18.9984 amu – 19.15708 amu
= – 0.1587 amu
The answer is in its negative form ( – 0.1587 amu) because the actual mass is less than the mass calculated from the total number of protons and neutrons.