AnswerCategory: ChemistryHow can the ionization energy
admin Staff asked 6 months ago

How can the ionization energy

How can the ionization energy of rubidium per atom be calculated if light of wavelength 5.84 x 10-8m produces electrons with a speed of 2.450 x 10 6 ms-1?

Are there any metallic compounds that do not react with acid or base?

What is the history of mercury drug?

After reaching saturation, if the temperature of the room continues to decrease for one more hour, h…

How can the mass of mixture of solids (initial), mass (g), and percentage of total mixture (%) be ca…

What is the number of moles and the mass of Barium peroxide (BaO2) needed to produce 2.500 kg of Bar…

1 Answers
admin Staff answered 6 months ago

Photon energy = Ionization Energy + Kinetic Energy
We get the energy of photon from the Plank’s equation, E = h f, where f is the frequency of the photon and h is the Plank Constant which is equal to 6.626 * 10^-34 Js
The kinetic energy of an electron is KE = 1/2 m v^2, where m is the mass, i. e., 9.11 * 10^-31 kg and the velocity v is 2.45 * 10^6 m/s
So it can be said that,
h f = IE + 1/2 m v^2
or, IE = h f – 1/2 m v^2
As c = f * λ, we can say that, IE = (h c) / λ – 1/2 m v^2
Putting the values we get, that,
IE = (6.626 * 10^-34 * 3 * 10^8) / (5.84 *10^-8) – {1/2 * 9.11 * 10^-31 * (2.45 * 10^6)^2}
= (3.404 * 10^-18) – (2.734 * 10^-18) J
= 6.7 * 10^-19 J
This is the ionization energy of an atom of Rubidium.